y=2根号x 1 x则dy-搜答案-大师作文网

y=2^cosx+sin√x,复合函数求导数y'=(2^cosx)ln2(﹣sinx)+cos√x*1/(2√x)dy={(2^cosx)ln2(﹣sinx)+cos√x*1/(2√x)}dx

我是这么做的,不知道对不对：令y/x=t则,y=tx则,dy/dx=t+xdt/dx由条件可知：dy/dx=2√t+t故：xdt/dx=2√t整理得：dt/√t=2dx/x两边积分,得：√t=lnx+

1/2*ln(x^2+y^2)=arctany/x两边对x求导,得1/2*1/(x^2+y^2)*(2x+2y*y')=1/[1+(y/x)^2]*(y'*x-y)/x^2化简得y'=(x+y)/(x

dy/√(1-y²)=dx/√(1-x²)所以arcsiny=arcsinx+Cy=sin(arcsinx+C),其中-2

∵y＝ln［x＋√（x^2＋a^2）］,∴e^y＝x＋√（x^2＋a^2）,∴（e^y－x）^2＝x^2＋a^2,∴2（e^y－x）（e^y－x）′＝2x,∴［x＋√（x^2＋a^2）－x］［（e^y

symsx;y=atan((x^2-1)^(1/2))-log(x)/((x^2-1)^(1/2))y=atan((x^2-1)^(1/2))-log(x)/(x^2-1)^(1/2)>>diff(y

这是我的解答,希望对你有帮助,有疑问请追问,若满意还望采纳,祝生活愉快!

请放心使用,有问题的话请追问采纳后你将获得5财富值.你的采纳将是我继续努力帮助他人的最强动力!

因为所以

dy/dx=2sin(x^4)cos(x^4)*4x^3复合函数求导dy^2/dx^2=[8x^3sin(x^4)cos(x^4)]^2dy/d(x^2)=2sin(x^4)cos(x^4)*2x^2

x(dx/dy)-y-√(x^2+y^2)=0,除以y:(x/y)(dx/dy)-1-√((x/y)^2+1)=0令x/y=u,代入：u(u+yu')=√(u^2+1)+1yu'=(√(u^2+1)+

正确答案：【-sin根号x/（2根号x）+2的x次方ln2】dx

dy=[-sin(√x)*1/2*x^(-1/2)-e^(-2x)*(-2)]dx=[1/2sin(√x)x^(-1/2)+2e^(-2x)]dx

dz=x/√(1+x^2+y^2)*dx+y/√(1+x^2+y^2)*dydz(1,1)=√3/3*(dx+dy)

∵(1+y²)dx+(xy-√(1+y²)cosy)dy=0==>√(1+y²)dx+(xy/√(1+y²)-cosy)dy=0(等式两端同除√(1+y

y=1/x^2,则dy

y=x^-2dy=-2x^-3dx=-2/x^3dx

（1）、移项：x*dy/dx=2-ydy/dx=(2-y)/x;dy/(y-2)=-dx/x;（2）进行积分：ln(y-2)=-ln(x)ln(y-2)=ln(1/x)+c（c是常数）y-2=1/x*

y=x^2(cosx+√x),dy=[2x(cosx+√x)+x²(-sinx+1/2*1/√x)]dx=[2xcosx-x²sinx+2x√x+1/2*x√x]dx=[x(2co

DY=[1/(x根号下lnx)-2e^(-2x)]Dx