y=4x-2分之1 求反函数
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因为x>-2,y∈Ry=1+In(x+2)则ln(x+2)=y-1e^(y-1)=x+2x=e^(y-1)-2所以反函数就是把x跟y换一下,范围也换一下即y=e^(x-1)-2(x∈R)
y=f(x+4)=2(x+4)/[1+3(x+4)]=(2x+8)/(3x+13)2x+8=(3x+13)y2x+8-3xy-13y=0(2-3y)x=13y-8x=(13y-8)/(2-3y)f(x
x=[10^(y-1)+3]/2
x=(2^y+1)/(2^y-1)x*2^y-x=2^y+1(x-1)2^y=x+12^y=(x+1)/(x-1)y=log2[(x+1)/(x-1)]
Y=X^2-2x显然制剂得到:Y=(X-1)^2-1是对称的,通过原点和轴x=1时,开放草图可以知道没有第三象限.方法二:点的第三象限坐标满足(负,负),Y=(X-1)^2-1,当x
1、y=x/3x+5的反函数为y=5x/(1-3x)(x≠1/3)2、求y=X^2的反函数是y=±√x(x≥0)3、y=3^(根号x-1/2)+1的反函数为y=1/2+[log3(x-1)]²
Y=(4X+1)/(5X-3)5yx-3y=4x+1(5y-4)x=3y+1x=(3y+1)/(5y-4)所以反函数为y=(3x+1)/(5x-4)(x≠4/5)
y=lg[4/(x+2)-1]10^y=4/(x+2)-14/(x+2)=10^y+1x+2=4/(10^y+1)x=4/(10^y+1)-2所以,反函数为:y=4/(10^x+1)-2但你的原式写的
y-π/4=ractan(2x-1)tan(y-π/4)=2x-1x=1/2[tan(y-π/4)+1]=1/2tan(y-π/4)+1/2∴反函数y=1/2tan(x-π/4)+1/2再问:不该考虑
首先,原函数的定义域为R,值域为R.令t=√(x^2+1)+x,则1/t=1/[√(x^2+1)+x]=√(x^2+1)-x,所以t-1/t=2x,x=(t-1/t)/2=(t^2-1)/(2t),由
你好,题不太清楚啊y=(2^x)/(2^x+1)y(2^x+1)=2^x(y-1)(2^x)=-12^x=1/(1-y)x=log2(1-y)(这里2是底数,1-y是真数)所以反函数是y=log2(1
y=2的X方-12的X方=y+1x=log2(y+1)y=log2(x+1)
1.y=2/xx=2/yy≠0所以反函数为y=2/xx≠02.y=(3-2x)/(x-1)=-2+1/(x-1)1/(x-1)=y+2x-1=1/(y+2)x=1+1/(y+2)=(y+3)/(y+2
y=2x+12x=y-1x=(y-1)/2所以y=2x+1的反函数是y=(x-1)/2y=x+1/x-2xy-2y=x+1xy-x=2y+1x(y-1)=2y+1x=2y+1/y-1所以y=x+1/x
2x+1=y(x+3)x(2-y)=3y-1x=(3y-1)/(2-y)所以反函数为y=(3x-1)/(2-x)
首先,原函数的定义域为R,值域为R.令t=√(x^2+1)+x,则1/t=1/[√(x^2+1)+x]=√(x^2+1)-x,所以t-1/t=2x,x=(t-1/t)/2=(t^2-1)/(2t),由
Y(X-1)=2X+3XY-Y=2X+3X(Y-2)=Y+3X=(Y+3)/(Y-2)也就是Y=(X+3)/(X-2)
y=(x+1)/2x=1/2+1/2x,定义域:{x丨x≠0},值域:{y丨y≠1/2}所以1/2x=y-1/2所以1/x=2y-1所以x=1/(2y-1)把“x”、“y”互换位置,得y=1/(2x-
由y=2x/(2x+1)得x=y/(2-2y)且x不等于-1/2假设y/(2-2y)=-1/2则可得2y=2y-2显然不成立故假设不成立,y/(2-2y)不等于-1/2同时2-2y不等于0则y不等于1