y^2-2xy 9=0方程所确定的隐函数的导数dy dx-搜答案-大师作文网

xy+e^y=y+1（1）求d^2y/dx^2在x=0处的值：（1）两边分别对x求导：y+xy'+e^yy'=y'y/y'+x+e^y=1(2)(2)两边对x再求导一次：(y'y'-yy'')/y'^

隐函数求导设z=x²y²-cos(xy)dy/dx=-(δz/δx)/(δz/δy)=-(2xy²+ysin(xy))/(2x²y+xsin(xy))=-y/x

-sin(xy)[ydx+xdy]=2xy^2*dx+x^2*2ydy-sin(xy)ydx-sin(xy)xdy=2xy^2*dx+2x^2*ydy-2x^2*ydy-sin(xy)xdy=2xy^

y^2/（x+y）=y^2-x^2y^2=（y^2-x^2）（x+y）两边同时求导得到：2yy’=(2yy’-2x)(x+y)+(y^2-x^2)(1+y’)2yy’=2yy’(x+y)-2x(x+y

红色圈出再问：那在试卷上怎么答呢再答：如果是大题目，直接写出这两个求导方程，像我这么叙述就行了，个人经验，仅供参考再问：能帮我再解以下另外那几个数学题吗再答：我尽力

两边对x求导,e^(2y)*2y'+3y+3xy'-2x=0,故dy/dx=y'=2x/[2e^(2y)+3x].

∵2x²y-xy²+y³=0==>4xydx+2x²dy-y²dx-2xydy+3y²dy=0==>(4xy-y²)dx=(2xy

dy²-2d(xy)+0=02ydy-2(xdy+ydx)=02ydy-2xdy=2ydxdy/dx=y/(y-x)

方程两边同时对x求导得2yy'-3(y+xy')=0整理化简得y'=3y/(2y-3x)即dy/dx=3y/(2y-3x)

图形为正方形,四个顶点为(0,2),(2,0),(0,-2),(-2,0)面积为8

对y^2－2xy＝7求微分,得2ydy-2(ydx+xdy)=0,∴（y-x)dy=ydx,∴dy/dx=y/(y-x).

xy'+y+sin(πy)πy'=0y'=-y/[x+πsin(πy)]

x-y+1/2siny=0F(x,y)=y-x-1/2siny=0F,Fx,Fy在定义域的任意点都是连续的,F(0,0)=0Fy(x,y)>0f'(x)=-Fx(x,y)/Fy(x,y)=1/(1-1

y^3z^2-x^2+xyz-5=0等式两边同时对x求导：∂z/∂x=（2x-yz）/（2zy^3+xy)等式两边同时对y求导：∂z/∂y=-(3y&#

将y看作是x的函数,则对x求导数有：3y^2*y'-3y'+2=0求出y'=2/3(1-y^2)其中y^2,y^3表示幂函数

设dy/dx=y'.求导,2yy'-2y-2xy'=0dy/dx=y'=y/(y-x)

两边对x求导,则2x-[e^y+x(e^y)y']=0整理得y'=(2x-e^y)/(xe^y)

第一步方程两边对x求导记y+xy'-y'/y=2x第二步解出y'记y'=(2xy-y^2)/(xy-1)

微分得xe^ydy+e^ydx+2ydy=0,解得dy/dx=-e^y/(xe^y+2y)

记p=√(x^2+y^2+z^2),则xyz+p=√2,p=√2-xyz两边对x求偏导得：yz+xyz'(x)+[x+zz'(x)]/p=0得：z'(x)=(-yz-x/p)/(xy+z/p)=-(p