φ0Cu2 Cu

由图可知:最高点是5；最低点是-5,所以A=5T=（7/4-1/4)π*2=3π所以ω=2π/3π=2/3即y=5sin(2/3*x+φ)图像过（π,0）代入的sin(2/3*π+φ）=0可得φ=1/

T=2π/ω=2π/3所以ω=3最小值为-2所以A=2图像经过(5π/9,0)所以有2sin(5π/3+φ)=0即sin(5π/3+φ)=05π/3+φ=kπ因为每个零点对应的是.-2π,-π,0,π

T=2π／3=2π／ω,∴ω=3.∵最小值为﹣2,∴A＝2.将﹙5π／9,0﹚代入函数,可得：2sin(5π／9×3＋φ）=0,解得：φ=kπ－5π／3.∵φ的绝对值＜π,∴﹣π＜φ＜π,即：∵﹣π＜

y=2sin(2x+π/6)f(0)=1f(π/2)=-11

f(x)=sin(ωx+φ)+cos(ωx+φ)=√2sin(ωx+φ+π/4）周期T=2π/ω=π∴ω=2f(-x)=f(x),则f(x)是偶函数则f(0)=±√2即φ+π/4=kπ+π/2即φ=k

f(x)=sin(wx+φ)+cos(wx+φ)=√2sin(wx+φ+π/4)T=2π/w=πw=2f(x)=√2sin(2x+φ+π/4)f(-x)=f(x),所以f(-π/8)=f(π/8)si

∵最大值为4∴A=4又最小半周期为6+2=8∴最小正周期T=8*2=16∴ω=2π/16=π/8又f(6)=0代入0=4sin(π/8*6+φ)sin(3π/4+φ)=03π/4+φ=kπφ=kπ-3

-A

∵sinΦ-cos（2Φ）=2sin²Φ+sinΦ-1=（2sinΦ-1）（sinΦ+1）∴sinΦ=1/2,或sinΦ=-1.∵0度≤Φ≤360度,∴Φ1=30°,Φ2=150°,Φ3=2

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sin(sinΦ)

f(x)=sin(ωx+φ)+cos(ωx+φ)=√2sin(ωx+φ+π/4)∵周期是π,∴ω=2∵f(-x)=f(x),∴φ+π/4=π/2,∴φ=π/4∴f(x)=√2sin(2x+π/2)=√

函数f(x)=sin(wx+φ)(w>0,|φ|0,|φ|φ=2π/3f(x)=sin(2x-2π/3+φ)=-sin2x==>φ=-π/3∵|φ|x=kπ+5π/122x-π/3=2kπ-π/2==

f(x)=sin(wx+φ){w>0,|φ|0,|φ|φ=π/6∴f(x)=sin(2x+π/6)2x+π/6=2kπ==>x=kπ-π/12；2x+π/6=2kπ+π==>x=kπ+5π/12；点对

已知函数f(x)=2sin(ωx+φ),φ>0,|φ|T=2π==>w=1f(x)=2sin(x+φ)==>f(π/4)=2sin(π/4+φ)=2==>π/4+φ=π/2==>φ=π/4f(x)=2

f(x)=√2sin(8（x/4+π/2)+φ）因为加了个π/2所以变成了cos所以变成偶函数

f(x)=√2sin(wx+φ+π/4)2π/w=πw=2f(x)=√2sin(2x+φ+π/4)f(-x)=√2sin(-2x+φ+π/4)f(x)=f(-x)sin(2x+φ+π/4)=sin(-

C函数f（x）=Asin（ωx+φ）的周期π,ω=2π,T=2；函数图象关于直线x=2π/3对称,2×2π/3+φ=kπ+π/2k∈Z,因为-π/2＜φ＜π/2,φ=π/6,函数的解析式为f（x）=A

T=π,w=2A=2,B=1Φ=-π/6f(x)=2sin(2x-π/6)+1f(kx)=2sin(2kx-π/6)+1周期为2π/32k=3k=3/2f(kx)=2sin(3x-π/6)+1x∈[0

f(x)=sin(wx+φ)+cos(wx+φ)=√2sin（x+π/4+φ）而f（x）是偶函数,故f（x）关于x=0对称所以π/4+φ=kπ+π/2（k是整数）而,|φ|