18X=19.8 7X的解
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(2x-3)(x-三分之一)=3x的平方-(x+1)(x-1)2x²-3x-2/3x+1=3x²-x²+111/3x=0x=0
设X²+3X为Y;Y-8=20/Y;Y²-8Y-20=0;(Y-10)(Y+2)=0;Y=10或-2;所以:1:X²+3X=10,X=2或-5;2:X²+3X=
x(x^2-2)+2x^2(x+3)-3x(5x-7)=x(3x^2-9x+17)+2=>x^3-2x+2x^3+6x^2-15x^2+21x=3x^3-9x^2+17x+2=>2x=2x=1
【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x
(X-3)平方-(X+3)*(X-3)=(X+1)*(X+2)-(X-1)*(X+4)x^2-6x+9-x^2+9=x^2+3x+2-x^2-3x+4-6x+18=66x=18-66x=12x=2
提出x得到:x*(1-1/2+1/2-1/3+1/3-1/4……+1/2008-1/2009)=2008接着:x*(1-1/2009)=2008最后:x=2009
2x^2-5x-x^2-2x=x^2-6-7x=-6x=6/7
36x÷x=1836x=18x18x=0x=0经检验:x=0是原方程的增根.∴原方程无实数根.
x^4-4x^3-4x^2+15x+18=0x^4-3x^3-x^3+3x^2-7x^2+21x-6x+18=0(x-3)(x^3-x^2-7x-6)=0x1=3x2=3.49449283705542
x(x+3)-x(1-2x)=1+3x²x²+3x-x+2x²=1+3x²x²+3x-x+2x²-3x²=12x=1x=2分之1
设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=
当x<0或者x>2时,f(x)=x³-2x²,f'(x)=3x²-4x.当0<x<2时,f(x)=2x²-x³,f'(x)=4x-3x².当
(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+
(x+x)+(x-x)+(xx)+(x/x)=1002x+0+x²+1=100x²+2x+1=100(x+1)²=10²x+1=10或x+1=-10x=9或x=
(x-3)(x+2)+18=x(x+1)x²-x-6+18=x²+xx+x=122x=12x=6
问题是不是X2=(X+30)*(X-18)啊?要是上面的话就这样X2=X*X-X*18+30*X-30*18=X2+12X-540移项得:X2-X2-12X=-540,即-12X=-540,X=45*
再答:望采纳,谢谢