(10x y)(10x (10-y))-搜答案-大师作文网

（3xy+10y)+[5x--(2xy+2y--3x)]=3xy+10y+5x--2xy--2y+3x=xy+8y+8x=xy+8(x+y)=--2+24=22.看来你在解题目时比较粗心,不知是那里搞

(3xy+10y)+5x-(2xy+2y-3x)=3xy+10y+5x-2xy-2y+3x=xy+8x+8y=-2+8(x+y)=-2+24=22

（3xy+10y)+[+5x-(2xy+2y-3x)]=3xy+10y+[+5x-2xy-2y+3x],[原式去括号]=3xy+10y+5x-2xy-2y+3x,[去括号]=3xy-2xy+5x+3x

[-(xy)/(x-y)^2]^4*[(x^2-xy)/x]^3*x^4/y^10÷[x/(xy-y^2)]^5=(x^4y^4)/(x-y)^8*(x-y)^3*x^4/y^10*[y^5(x-y)

7.x*x+2*x+y*y-6y+10=(x+1)*(x+1)+(y-3)*(y-3)=0x+1=0且y-3＝0所以x*y＝-38.再加个4*x就好了11.原式＝（x-2）*（x-2）+（y+3）*（

[（xy+2）（xy-2）-2x2y2+4]÷（xy）=（x2y2-4-2x2y2+4）÷xy=-x2y2÷xy=-xy,当x=10,y=1/25时,原式=-2/5．

[(xy+2)(xy-2)-2x^2y^2+4]/(xy)=[(x^2y^2-4)-2x^2y^2+4]/(xy)=-x^2y^2/xy=-xy=-10*(-1/25)=2/5

x y xy=10怎么算

2xy=10xy=5

(3xy+10y)+[5x-(2xy+2y-3x)]=3xy+10y+5x-2xy-2y+3x=3xy-2xy+10y-2y+5x+3x=(3xy-2xy)+(10y-2y)+(5x+3x)=xy+8

X+y=10,XY=24,则X=4,Y=6或X=6,Y=4,所以(X-Y)(X-Y)=2*2=4或（-2）*（-2）=4,都为4

x²+y²=(x+y)²-2xy=10²+2=102

1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析：通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因

x^2-10x-11=(x-10)(x+1)x^2y^2-16xy+60=(xy-10)(xy-6)(x+y)^2-7(x+y)-18=(x+y-9)(x+y+2)x^2-13xy-30y^2=(x-

x的平方y+10xy+25y=y（x²+10x+25）=y（x+5）²

xy+yx=10x,y是多少

xy+yx=10x+y+10y+x=11x+11y=100+x10x=100-11yx=10-1.1y所以y只能是0

(-2xy+2x+3y)-(3xy+2x-2y)-(x+4y-xy)=-2xy+2x+3y-3xy-2x+2y-x-4y+xy=-4xy-x+y=-4xy-(x-y)=-4×(-4)-10=6

步骤如下:x^2y^2-8xy+16=-(x^2+y^2-2xy)(xy-4)^2=-(x-y)^2所以得出等式左右都为0!计算得出x=2,y=2

因为：xy=(x-10)(y+1)→xy=xy+x-10y-10①xy=(x-15)(y+3)→xy=+3x-15y-45②由①、②得：x=10y+10③x=5y+15④将③‐④得：10y+

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-