一个整数反向输出JAVA
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分两步呗.第一步:生成随机数第二步:排序这里只说第一步的内容,第二步,我想你的算法书中都有说吧.先说生成一个0-1之间的随机数很容易吧?doublek=Math.Random();而获得一个0-100
importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System
importjava.io.*;classSEV{publicstaticvoidmain(String[]args)throwsIOException{intmax,min;doublesh;Inp
importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin
publicclassCat{publicstaticvoidmain(String[]args){intnum=2;drawDiamond(num);}privatestaticvoiddrawDi
publicclassTest{publicstaticvoidmain(String[]args){inta=1203;intsum=0;while(a/10!=0){sum
staticvoidBubbleSort(inta[]){inttemp=0;for(inti=0;ifor(intj=0;jif(a[j]>a[j+1]){//把这里改成大于,就是升序了temp=a
#includevoidmain(){inta,i=0,b[3];printf("inputathreebitnumber\n");scanf("%d",&a);if(a>=100&&a=0;j--)
方法很多嘛随便来一个:#include#includevoidmain(){charp[10];char*q;inti=0;scanf("%s",p);q=p;while(*(q++))i++;q--
Scannerscanner=newScanner(system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy
importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整
importjava.util.Scanner;publicclassjiechen{publicstaticvoidmain(String[]args){Scannerscanner=newScan
publicvoidscanner(){\x09\x09intarr[]=newint[5];//存储输入数据\x09\x09inttemp;\x09\x09\x09\x09//用于数据交换\x09S
importjava.util.Scanner;publicclassMath11{publicstaticvoidmain(String[]args){Scanners=newScanner(Sys
publicclassTest{publicstaticvoidmain(String[]args){intn=20;int[]array=newint[n];java.util.R
Randomizea=Fix(Rnd()*90)+10Printaa=a\10+(a-(a\10)*10)*10Printa
//eg1.javaimportjava.util.*;publicclasseg1{publicstaticvoidmain(String[]args){inta=0,b=0,c=0,max=0;S
importjava.util.*;publicclassExercise06{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S
楼上说没错,while(X)是先进行X判断然后再执行{语句体},而do..while则是先执行do{语句体},再判断while(X),这样会导致do..while比while执行语句体的次数多一次再问