设Sn为数列〔An〕的前n项和,已知S3等于7,A1+3,3A2,A3+4构成等差数列 1:求A2的
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设Sn为数列〔An〕的前n项和,已知S3等于7,A1+3,3A2,A3+4构成等差数列 1:求A2的
设Sn为数列〔An〕的前n项和,已知S3等于7,A1+3,3A2,A3+4构成等差数列
1:求A2的值
2:若{An}是等比数列,且An+1<An(n为正整数),试求Sn的表达式
设Sn为数列〔An〕的前n项和,已知S3等于7,A1+3,3A2,A3+4构成等差数列
1:求A2的值
2:若{An}是等比数列,且An+1<An(n为正整数),试求Sn的表达式
S3 = A1+A2+A3 = 7
3A2-A1-3 = A3+4 - 3A2
6A2 = A1+A3 + 7
A1+A3 = 6A2 -7
A2 = 2
2.A2 = A1 * r so A1 = A2/r = 2/r
A3 = A2 * r so A3 = 2r
2/r + 2 + 2r = 7
2r^2 -5r + 2 = 0
(2r - 1)(r-2) = 0
r = 1/2
A1 = 4
A2 = 2
A3 = 1
Sn = (1-(1/2)^n) * 2 * 4 = 8 (1-1/2^n)
3A2-A1-3 = A3+4 - 3A2
6A2 = A1+A3 + 7
A1+A3 = 6A2 -7
A2 = 2
2.A2 = A1 * r so A1 = A2/r = 2/r
A3 = A2 * r so A3 = 2r
2/r + 2 + 2r = 7
2r^2 -5r + 2 = 0
(2r - 1)(r-2) = 0
r = 1/2
A1 = 4
A2 = 2
A3 = 1
Sn = (1-(1/2)^n) * 2 * 4 = 8 (1-1/2^n)
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