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(X-20)/3+(X-18)/5+(X-16)/7+(X-14)/9+(X-12)/11=5

来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/11/10 22:41:44
(X-20)/3+(X-18)/5+(X-16)/7+(X-14)/9+(X-12)/11=5
(X-20)/3+(X-18)/5+(X-16)/7+(X-14)/9+(X-12)/11=5
把式子拆分
x/3+x/5+x/7+x/9+x/11= 20/3+18/5+16/7+14/9+12/11+5
观察上式子由于右边式子分子加分母都等于23 ,而5=3/3+5/5+7/7+9/9+11/11
因此左式=23/3+23/5+23/7+23/9+23/11
所以x=23
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550 x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+. (X-20)/3+(X-18)/5+(X-16)/7+(X-14)/9+(X-12)/11=5有没有简便计算 -6x+3=2x+11 x=3/2x+14 3/4x-6=3/2x+3 20-3x=7x+4 5/9x+2=1/3x+4 计算:(1/X^2+3X+2)+(1/X^2+5X+6)+(1/X^2+7X+12)=(1/X^2+9X+20) |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| (2x-1)/(x-1)(x-2)=(x-5)/(x-2)(x-3) x/2x^2-11x-21=(x+7)/x^2-1 y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1 设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10), x+3/x+1-x+5/x+3-x+7/x+5+x+9/x+7=0 解方程:(x+3)/(x+2)-(x+5)/(x+4)=(x+7)/(x+6)-(x+9)/(x+8)