1、{1÷3}x=9-[2÷3]x x=
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
若x等于它的倒数则(x-1)(x+2)/x-1÷x^2-9/x+3=
x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
x+2/x+3-x+1/x+2=x+8/x+9-x+7/x+8
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
先化简代数式再求值(3/x+1 - x+1)÷x²-2x/x+1,其中x满足方程x/x-1+1/x=1
已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷(x^2+x-6)/(x^2+
先化解,在求值;(3x/x-1-x/x+1)÷x四次方-4x²/x³-x,其中x=根号2+2
先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2
2x/x^2-9=x-1/x^2-6x+9-1/x+3