求化简下:f(x)=sin(x+π/4)+2sin(x-π/4)-4cos2x+3cos(x+3π/4)
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
已知函数f(x)=(4cos^4x-2cos2x-1)/[sin(π/4+x)·sin^2(π/4-x)]化简
已知函数f(x)=(4cos^4x-2cos2x-1)/[sin(π/4+x)·sin(π/4-x)]化简
已知函数f(x)=2sin²(π/4+x)-根号3cos2x
已知函数f(x)=2sin^2(π/4+x)-根号3cos2x
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,
已知函数f(x)=cos2x/[sin(π/4-x)]
求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x
函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
化简函数f(x)=[(1+cos2x)²-2cos2x-1]/[sin(π/4+x)*sin(π/4-x)]
f(x)=((1+cos2x)^2-2cos2x-1)/(sin(π/4+x)sin(π/4-x))