(2x-3x)^2(2x+3y)^2
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/11 11:49:47
(2x-3x)^2(2x+3y)^2
(2+xy)(xy-2)-(-2+xy)^2
(a+3b)^2-(2a-3b)(3b+2a)
(2+xy)(xy-2)-(-2+xy)^2
(a+3b)^2-(2a-3b)(3b+2a)
=[(3x+2y)+(2x+3y)][(3x+2y)-(2x+3y)]
=(5x+5y)(x-y)
=5(x+y)(x-y)
(2)3x^3-12xy^2
=3x(x^2-4y^2)
=3x(x+2y)(x-2y)
(3)a^2b^2-4ab+4;
直接用完全平方
=(ab-2)^2
(4)a^2+16b^2+8ab
直接用完全平方
=(a+4b)^2
(5)1-x+1/4a^2
错了,应该是1-a+1/4a^2
直接用完全平方
=(1-1/2a)^2
(6)-4a^2x^2+12ax-9.
=-(4a^2x^2-12ax+9)
=-(2ax-3)^2
=(5x+5y)(x-y)
=5(x+y)(x-y)
(2)3x^3-12xy^2
=3x(x^2-4y^2)
=3x(x+2y)(x-2y)
(3)a^2b^2-4ab+4;
直接用完全平方
=(ab-2)^2
(4)a^2+16b^2+8ab
直接用完全平方
=(a+4b)^2
(5)1-x+1/4a^2
错了,应该是1-a+1/4a^2
直接用完全平方
=(1-1/2a)^2
(6)-4a^2x^2+12ax-9.
=-(4a^2x^2-12ax+9)
=-(2ax-3)^2
有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-
因式分解3x^2(x-y)+6x(y-x)
化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方
【x-3y][x+y]-[x-2y][x +2y]-[x-y
[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)
x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
计算(x+y)(x+y)^2(-x-y)^3
数学(x-y)^5*(y-x)^3*(x-y)^2
已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
化简:{2/3x-2/(x+y)[(x+y)/3x-x-y]}/【(x-y)/x】的负二次方