解7x^2-6x+1=0

已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值 解方程(x+1/x+2)-(x+2/x+3)=(x+5/x+6)-(x+6/x+7) 解方程：x+2/x+1-x+3/x+2=x+6/x+5-x+7/x+6 解方程：x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6) 解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) 解方程(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=0 解一道初一的分式方程（x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的 已知方程x/x+1+x+6/x+7=x+1/x+2+x+5/x+6的解是x=-4.试求出x+62/x+63+x+68/x 2\x+2-(1)\x-2=0解方程并验算 (7\x^2+x)+(3\x^2-x)=(6\x^2-1)