化简f(x)=(1-√2*cos(2x-π/4))/sin(π/2-x)
化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x)
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
已知f(x)=cos^2x/1+sin^2x求f'(π/4)
已知函数f(x)=(1+1/tanx)sin(x)^2 -2sin(x+π/4)*cos(x+π/4)
f(x)=2SIN^2(x+π\4)-cos(2x+π\6) 化简 谢
已知函数f(x)=sin²(π/4+x)+cos²x+1/2求最值
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
已知函数f(x)=2sin(x/4)cos(x/4)-2√3sin²(x/4)+√3,且g(x)=f(x+π/
已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4)
已知函数f(x)=2cos^2 x+2sinxcosx-1 化简后f(x)=√2sin(2x+π/4) 求f(x)在[0