帮忙解道题 ,已知x+1/y=y+1/z=z+1/x ,证明x+y+z=1
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帮忙解道题 ,已知x+1/y=y+1/z=z+1/x ,证明x+y+z=1
∵x+1/y=y+1/z ∴x-y=1/z-1/y=(y-z)/yz.(1) ∵y+1/z=z+1/x ∴y-z=1/x-1/z=(z-x)/xz.(2) ∵x+1/y=z+1/x ∴z-x=1/y-1/x=(x-y)/(xy).(3) (1)*(2)*(3)得:(x-y)(y-z)(z-x) = (x-y)(y-z)(z-x)/(x^2y^2z^2).(4) ∵x,y,z 为互不相等的非零实数 ∴(4)式两边除以(x-y)(y-z)(z-x) 得:1 = 1/(x^2y^2z^2) x^2y^2z^2 = 1
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