2sina(x-π/4)sin(x+π/4) 怎么转换成(sinx-cosx)(sinx+cosx)?
化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)
求证sinx-cosx=根号2sin(x-π/4)
sinx+cosx=√2sin(x+π/4)
2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a
求证:tan(x-π/4)=(sinx-cosx)/(sinx+cosx)
f(x)=cos(2x-π/3)+2sin(x-π/4)怎么化简成(sinx-cosx)(sinx+cosx)
利用cosx=sin(π/2-x),sin'x=cosx,证明(cosx)'=-sinx
化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1
求sinx+cosx=根号2sin(x+π/4)的解释?为什么?怎么算?
cosX+sinX=根号2sin(X+π/4)是怎么推出来的,
函数fx=sinx+cosx导数怎么是√2sin(x+π/4)?
(sin^x/sinx-cosx)-sinx+cosx/tan^2x-1