这是初中的算术题.2x-y=3 3x-y+Z=8.X-2y+3z=3这三个方程放一起求xyz的值.怎么求?急
设X+Y+Z=0求X^3+X^2Z-XYZ+Y^2Z+Y^3的值
已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值
已知xyz适合关系式√3x+y-z-2+√2x+y-z=√x+y-2011+2011-x-y,试求xyz的值
已知x+y+z=0,求多项式x^3+x^2z-xyz+y^3的值
若 x/2等于y/3等于z/4,且x+y-z=5 求xyz的值
设函数z=z(x,y)由方程x^2+y^3-xyz^1=0确定,求z/x,z/y
已知x+y+z=3,x^2+y^2+z^2=29,x^3+y^3+z^3=45,求xyz的值.
X+Y+Z=3 X^2+Y^2+Z^2=29 X^3+Y^3+Z^3=45 求XYZ的值
已知x+y+z=3,x^2+y^2+z^2=29,x^3+y^3+z^3=45,求xyz的值
已知x,y,z同时满足2x-3y=8,3y+2z=0,x-z=-2,试求xyz的值
已知3/x+y=4/x+y=5/y+z,求xyz/(x+y)(y+z)(z+x)的值
已知方程组{2X-Y+3Z=0,X-3Y+Z=0(XYZ≠0),求3Y分之4X+2Z的值