X²-3XY+2Y² =(x-y)(x-2y) .(x-2y) 是怎么算出来的?
X²-3XY+2Y² =(x-y)(x-2y) 中(x-2y) 是怎么算出来的?
已知2x+y=4,xy=3,求代数式2x²y+xy² 我算出来的是2xy(x+y) 有错吗 有就指出
2x²-3xy=y²=0(x,y不得o)求x/y+y/x
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
已知x-3y=0,y≠0,求x²-2xy+y²分之2x+y×(x-y)的值
已知xy=2,x-y=3,求(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y的值.
已知xy=-2,x-y=3,求(x+y)(x-y)-y平方+(x-y)平方-(6x2y-2xy平方)/2y的值
当x=2,y=-1时,求代数式(x+y)(x-y)+(x-y)²-(x²-3xy)的值
已知y=(x²-3xy-2y²)/2y,则x:y的值为
初中数学分式已知x/y=2,求(x*x-xy+3y*y)/x*x+xy+6y*y的值
x根号x+x根号y/xy-y^2)-(x+根号xy+y/x根号x-y根号)y
3x²y+xy²-[2xy²-4x²y+(x²y-2xy²)