求助三道高一数学三角函数题
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求助三道高一数学三角函数题
1、用tan(alpha)表示tan(alpha/2)
2、化简:sin(50)(1+根号3tan(10))(角度)
3、求证:(1-tan^2(alpha/2))/(1+tan^2(alpha/2))=cos(alpha)
详细过程,谢谢
1、用tan(alpha)表示tan(alpha/2)
2、化简:sin(50)(1+根号3tan(10))(角度)
3、求证:(1-tan^2(alpha/2))/(1+tan^2(alpha/2))=cos(alpha)
详细过程,谢谢
1
tan(alpha)=2tan(alpha)/(1+tan^2(alpha/2))
2
2sin(50)(1/2+根号3/2tan(10))
=2sin(50)/cos10(1/2cos10+根号3/2son(10))
=2sin(50)/cos10*sin40
=2sin(50)cos50/cos10
=sin100/cos10=1
3
:(1-tan^2(alpha/2))/(1+tan^2(alpha/2))=
切化弦 太不好输入 讲就下思路 通分 运用二倍角就可以了
tan(alpha)=2tan(alpha)/(1+tan^2(alpha/2))
2
2sin(50)(1/2+根号3/2tan(10))
=2sin(50)/cos10(1/2cos10+根号3/2son(10))
=2sin(50)/cos10*sin40
=2sin(50)cos50/cos10
=sin100/cos10=1
3
:(1-tan^2(alpha/2))/(1+tan^2(alpha/2))=
切化弦 太不好输入 讲就下思路 通分 运用二倍角就可以了