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(x^2+4y^2-2xy)(x^2+4y^2+2xy)(x+2y)(x-2y)

来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/11/10 14:20:31
(x^2+4y^2-2xy)(x^2+4y^2+2xy)(x+2y)(x-2y)
(x^2+4y^2-2xy)(x^2+4y^2+2xy)(x+2y)(x-2y)
(x^2+4y^2-2xy)(x^2+4y^2+2xy)(x+2y)(x-2y) =(x-2y)^2(x+2y)^2(x+2y)(x-2y) =(x-2y)^3(x+2y)^3 =(x^2-4y^2)^3
x^2y+4xy+4y （xy-x^2)乘以(xy)/(x-y) (x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy) （x^2+xy/x-y)/（xy/x-y)计算 因式分解：x×x-xy-2y×y-x-y 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? 计算:4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2 作乘法:(x+y)(x^2-xy+y^2)；(x-y)(x^2+xy+y^2) (x+y-2xy)(x+y-2)+(1-xy)² (x^2-xy)y÷y-x/xy怎么做? （-3x^y+2xy)-( )=4x^+xy xy-[x+2y+0.5(x-4)*(y-2)]