x+y-1=xy/（x+y-xy）怎么因式分解

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/09/25 18:24:47

x+y-1=xy/(x+y-xy)
(x+y-1)(x+y-xy)=xy
(x+y)²-(xy+1)(x+y)+xy=xy
(x+y)²-(xy+1)(x+y)=0
(x+y)[(x+y)-(xy+1)]=0
(x+y)(x+y-xy-1)=0
再问：好像没化简完、、
再答：嗯，是的。继续：
x+y-1=xy/(x+y-xy)
(x+y-1)(x+y-xy)=xy
(x+y)²-(xy+1)(x+y)+xy=xy
(x+y)²-(xy+1)(x+y)=0
(x+y)[(x+y)-(xy+1)]=0
(x+y)(x+y-xy-1)=0
(x+y)[(x-xy)+(y-1)]=0
(x+y)[x(1-y)-(1-y)]=0
(x+y)(1-y)(x-1)=0
(x+y)(x-1)(y-1)=0

xy+x+y+1因式分解 1-x-y+xy 因式分解因式分解xy-x-y+1 xy-x-y+1因式分解 (xy+1)(x+1)(y+1)+xy怎么因式分解因式分解（xy-x）+（1-y）因式分解 x2(x+1)-y(xy+x) 因式分解：（x+y）（x+y+2xy）+（xy+1）（xy-1）=______．因式分解x2+y-xy-x （x+y)*（x+1)-(xy+y*y)因式分解为多少因式分解:x^2y+xy^2=? （xy-x-y+1)^2因式分解