2x+2y=16; 3x+4y=29;的解 3x+4y=29; 3x+4y=29;
已知x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
(x+y)(x+2y)(x+3y)(x+4y)=-40
已知X^2-4X+Y^2-10Y+29=0,求X^2Y^2+2X^3Y^2+X^4Y^2
已知x^2-4x+29-10y+y^2=0,求x^2y^2+2x^3y^2+x^4y^2
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y/2x-y的值
若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值?
若X=负四分之一,能否确定代数式(2X-Y)(2X+Y)+(2X-Y)(Y-4X)+2Y(Y-3X)的值?