2x²-5X-12
((x²-5x+6)/(12-7x+x²))²÷((x²+3x+2)/(x
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
(2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x
已知x -2x=5,求代数式x四次方+3x³-12x² -31x-15
1/x²+x+1/x²+3x+2+1/x²+5x+6+1/x²+7x+12,分式
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
x(x²-1)+2x²(x+1)-3x(2x-5)计算
(x-2)(x-3)+2(x+6)(x-5)-3(x²-7x+13)化简
(x-2)(x-3)+2(x-5)(x+6)-3(x^2-7x+12)
(x+2)(x-12)+(x+7)(x+8)+(x+5)(x-10),化简.