根据下列条件求函数f(x)=sin(x+π/4)+2sin(x-π/4)-4cos 2x+3cos(x+3π/4)的值

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根据下列条件求函数f(x)=sin(x+π/4)+2sin(x-π/4)-4cos 2x+3cos(x+3π/4)的值
（1）x=π/4
（2）x=3π/4

f(π/4)
=sin(π/4+π/4)+2sin(π/4-π/4)-4cosπ/2+3cos(π/4+3π/4)
=sinπ/2+2sin0-4cosπ/2+3cosπ
=1+0-0-3
=-2
f(3π/4)
=sin(3π/4+π/4)+2sin(3π/4-π/4)-4cos3π/2+3cos(3π/4+3π/4)
=sinπ+2sinπ/2-4cos3π/2+3cos3π/2
=0+2-0+0
=2

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