x-1/(x+1)²-4 和 1-x/2-4x+2x²

(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 (4x³)²×[x³-x(2x-1)] 化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以（2-x） 计算:2x/(x-2)(x+1)÷(1－x/x+1)-x²+2x/x²-4? [（x+2）/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x (x+1)/(x²+3x+2)+(x²-2x)/(x²-4) x²-2x分之x+2-x²-4x+4分之x-1 x+2/x²-2x-x-1/x²-4x+4计算 解方程(x²-x+4)x-(x-1)(x²+2)=x+7 (x+2)/x(x-2)-(x-1)/x²-4x+4=几, x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x