√{3+√[5-√(13+√48)]}/(√6+√2),怎么化简啊,
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/15 17:12:15
√{3+√[5-√(13+√48)]}/(√6+√2),怎么化简啊,
√{3+√[5-√(13+√48)]}/(√6+√2)
=√{3+√[5-√(12+4√3+1)]}/(√6+√2)
=√{3+√[5-√(2√3+1)²]}/(√6+√2)
=√{3+√[5-(2√3+1)]}/(√6+√2)
=√{3+√[4-2√3]}/(√6+√2)
=√{3+√[3-2√3+1]}/(√6+√2)
=√{3+√[√3-1]²}/(√6+√2)
=√{3+(√3-1)}/(√6+√2)
=√{2+√3}/(√6+√2)
=√{4+2√3}/√2/(√6+√2)
=√{√3+1}²/[√2*(√6+√2)]
=(√3+1)/[√2√3+2]
=(√3+1)/[2(√√3+1)]
=1/2
=√{3+√[5-√(12+4√3+1)]}/(√6+√2)
=√{3+√[5-√(2√3+1)²]}/(√6+√2)
=√{3+√[5-(2√3+1)]}/(√6+√2)
=√{3+√[4-2√3]}/(√6+√2)
=√{3+√[3-2√3+1]}/(√6+√2)
=√{3+√[√3-1]²}/(√6+√2)
=√{3+(√3-1)}/(√6+√2)
=√{2+√3}/(√6+√2)
=√{4+2√3}/√2/(√6+√2)
=√{√3+1}²/[√2*(√6+√2)]
=(√3+1)/[√2√3+2]
=(√3+1)/[2(√√3+1)]
=1/2