tan(a+π/4)=2 a∈(0,π/2),求tana
已知tana/2=2求tan(a+π/4)
已知tana=2,求tan(a-π/4)
已知:tana=2,则tan(a+π/4)
求证tana+seca=tan(a/2+π/4)
cos(π-a)tan(a-2π)tan(2π-a) /sinπ+a = -tana求过程
已知1-tanA/1+tanA=2+根号3,则tan(π/4+A)是
求证tan(a+π/4)=(1+tana)/(1-tana)
tan(a+π/4)=-1/2,求2cosa(sina-cosa)/(1+ tana)
tana+1/tana=3,求sina*cosa tan^2 a+1/tan^2 a
tana满足等式tan²a-4tana+4=0,求2sin²a+sinacosa+cos²
tan(a+b)=2/5,tan(a-b)=1/4,求tana,tanb,tan2a
已知tana是方程5x-7x-6=0的根,求sin(π/2-a)cos(π-a)tana/sinasin(π+a)tan