(16x²y³z-8x³y²z)÷(-8x²y²)=
若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值
x³+y³+z³-3xyz为什么等于(x+y+z)(x²+y²+z
初一 下 数学 1、已知3x-4y-z=0,2x+y-8z=0,求 x²+y²-z²÷xy
1、x³+x²y-x²z-xyz
求方程组8x-y-z=16 x²+y²+z²=1990 的正整数解
已知x+y+z=0,求(y²+z²-x²)分之1+(z²+x²-y
已知x,y,z为正整数,且满足x³-y³-z³=3xyz,x²=2(y+z),求
已知3x-4y-z=0 2x+y-8z =0,求(x²+y²-z²)/(xy+yz)的值
(x-3y+2z)²=
(-3x²y³z) * x³(x²y)² ÷ 9x⁴y五次
(x-z-20)²+(3x-6y+3)²+|3y+2z-8|=0 求x z y
已知x²+y²+z²-2x+4y-6z+14=0,求x+y-z/x+y+z的值