For all numbers x and y,let x∆y be defined

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For all numbers x and y,let x∆y be defined
as x∆y = x2 + xy + y2
.What is the value
of (3∆1)∆1?
英文看不懂不要紧

对于所有的数字X和Y ,定义x∆y 为X的平方加上Y的平方加上X与Y的积
那么,(3∆1)∆1等于多少
以上是这道题的翻译,现在懂了吧?
所以此题答案:3∆1=3^2+3*1+1^2=13
(3∆1)∆1=13∆1=13^2+13*1+1^2=184

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