(1-1/2004)(1-1/2003)(1-2002)...(1-1/3)(1-1/2)=

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/19 22:18:37

(1-1/2004)(1-1/2003)(1-2002)...(1-1/3)(1-1/2)=
要有计算过程

(1-1/2004)(1-1/2003)(1-2002)...(1-1/3)(1-1/2)
=(2003/2004)(2002/2003)(2001/2002)...(2/3)(1/2)
中间约分约掉了
=1/2004

1/2001*2002+1/2002*2003+1/2003*2004+1/2004*2005+1/2005=?/? |1/2004-1/2003|+|1/2003-1/2002|+|1/2002-1/2001|+|1/2001-1/20 化简：|1/2004-1/2003|+|1/2003-1/2002|+|1/2002-1/2001|-|1/2001-1 |1/2004-1/2003|+|1/2002-1/2003|+.+|1/2-1|等于多少 |1/2004-1/2003 2003+2002*2004分之2003*2004-1 2002/2002又2002/2003+1/2004 计算:{1\2005-1/2004}+{1/2004-1\2003}+{1/2003-1/2002}+……+{1/3-1 |1／2003—1／2002|+|1／2004—1／2003|—|1／2004—1／2003| (1/2004 -1)(1/2003 -1)(1/2002 -1).(1/1001 -1)(1/1000 -1) （根号3+1）^2004-2(根号3+1)^2003-2(根号3+1)^2002+2004 |1\2003-1\2002|-|1\2004-2002|+|1\2004-1\2003| 简便算法 1/2001*2002+1/2002*2003+1/2003*2004+1/2004+2005+1/2005