设集合A={(x,y)|(x-2)^2+y^2=1,xy∈R},B={(x,y)|2m≤x+y≤2m+1,xy∈R},若
集合M={(x,y)|y=k(x-1)+1,xy∈R},N={(x,y)|x^2+y^2-2y=0,xy∈R},则M∩N
设集合A={x//x-2/≤2,x∈R},B={y/y=-x^2,-1
设XY∈R集合A={(x,y)|x²-y²=1},B={(x,y)|y=t(x+2)+3},若A∩B
若全集I={(x,y)|x,y∈R},集合M={(x,y)|(y-3)/(x-2)},N{(x,y)|y=x=1},则(
设集合A={(x,y)|2x+y=1,x、y∈R},集合B={(x,y)|a2x+2y=a,x,y∈R},若A∩B=∅,
设集合M={(x,y)|x^2+y^2=1.x∈R,y∈R},N={(x,y)|x-y=0,x∈R,y∈R},则集合M∩
设A={(x,y)|y=-2x+3,x,y∈R},B={(x,y)|y=(4m-3{m}^{2})x+1,x,y∈R},
设集合A={y y=x²-2x+2,x∈R},U=R,B={x -1≤x≤1}
设A={(x,y)|y=-2x+3,x,y∈R},B={(x,y)|y=(4-3m^2)x+1,x,y∈R},求A∩B≠
设全集U={(x,y)|x,y属于R},集合M={(x,y)|(y+2)除以(x-2)=1},N={(x,y)|y不等于
设全集U={(x,y)|x,y属于R},集合M={(x,y)|(y-3)除以(x-2)=1},N={(x,y)|y不等于
设集合M={y|y=x²,x∈R},N={y|y=2-|x|,x∈R},则M∩N?