tanx=5/12,tany=4/3.x属于0,90,y属于180,270,求sin(x+y)
证明 (tanX+tanY)/(tanX-tanY)=(sin(X+Y))/(sin(X-Y))
求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)(详细步骤)
已知TanX,TanY是方程X^-3X-3=0的俩根,求sin^(x+y)-3sin(x+y)cos(x+y)-3cos
sin(x+y)=1\2,sin(x—y)=1\3,求[tan(x+y)-tanx-tany]\[tany的平方tan(
已知tanx,tany是方程x平方+Px+Q=0的两个根求sin(x+y)平方+
已知tanx=2,tany=3,x,y∈(0,π/2),求x+y.
已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
实数x,y满足tanx=x,tany=y,且|x|≠|y|,则sin(x+y)x+y−sin(x−y)x−y
若x、y是锐角且tanx=2/3tany=3/4则sin(x+y)等于
已知x,y,z都是锐角,sin^2x+sin^2y+sin^2z=1,求tanx*tany*tanz的最值
已知tanx=1/4,tany=-3,求tan(x+y)的值
已知tanx=-3/4,且tan(x+y)=1,求tany的值