limx趋向无穷[(x^2+1)/(x+1)]-(ax+b)=1 求a,b

lim趋向正无穷(根号下X^2+X-1 -AX)=b ,求a ,b limx->无穷【x^2+1]/[x+1]-ax-b=2 求a和b的值 lim(x趋向正无穷)(根号(1+x^2)-ax-b)=1,求a,b的值 1.若lim x趋向无穷 (（4x^2+1）/(x+1)-ax+b)=0,求a,b的值 根号下（x平方-x+1-ax-b）=0当x趋向无穷时的极限为零,求a.b值 求极限 limx趋向无穷(2x+3/2x+1)∧x+1 limx趋向于无穷x²-1/2x²-x-1求极限 求极限limx趋向无穷 ((1-2x) /(2-2x))^x 已知 lim(x趋向于正无穷){5x-√(ax^2-bx+1)}=1,求常数a、b的值 求极限,limx趋向于正无穷ln(1+3^x)/(1+2^x) 若极限limx→∞【4x^2+3/x-1+ax+b】=0.求常数a b.求极限limx→∞(√ 已知limx→∞[(x^2+1)/(x+1)-(ax+b)]=0,求常数a,b的值