大师作文网[x(x²y-xy)-y(x²-x³y)]÷3x²y
来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/10/03 06:36:32
[x(x²y-xy)-y(x²-x³y)]÷3x²y
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
![[x(x²y-xy)-y(x²-x³y)]÷3x²y](/uploads/image/z/17096899-67-9.jpg?t=%5Bx%28x%26%23178%3By-xy%29-y%28x%26%23178%3B-x%26%23179%3By%29%5D%C3%B73x%26%23178%3By)
[x(x²y-xy)-y(x²-x³y)]÷3x²y
=x^2y[(x-1)-(1-xy)]÷3x²y
=[(x-1)-(1-xy)]÷3
=(x-2+xy)/3
再问： [x(x²y²-xy)-y(x²-x³y)]÷3x²y 刚才打错了 这个是原题
再答： [x(x²y²-xy)-y(x²-x³y)]÷3x²y =x^2y[(xy-1)-(1-xy)]÷3x²y =[(xy-1)-(1-xy)]÷3 =-2/3
=x^2y[(x-1)-(1-xy)]÷3x²y
=[(x-1)-(1-xy)]÷3
=(x-2+xy)/3
再问： [x(x²y²-xy)-y(x²-x³y)]÷3x²y 刚才打错了 这个是原题
再答： [x(x²y²-xy)-y(x²-x³y)]÷3x²y =x^2y[(xy-1)-(1-xy)]÷3x²y =[(xy-1)-(1-xy)]÷3 =-2/3
[x（x²y²-xy）-y（x²-x³y）]÷3x²y
【x(x²y²-xy)-y(x²-x³y)】÷3x²y
因式分解：[x（x²y²-xy）-y（x²-x³y）]÷3x²y
x²/xy-x/y
急![(3x+y)²-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy)
[-xy/(x-y)²]²×(y²-xy/x)³
化简x-y分之x + x³-2x²y+xy²分之y³ ÷ y²-x&#
计算：(xy-x²)×x-y/xy
x-y/x²÷x²-2xy+y²/xy*（xy-x²）
【(1)/(x-y)+(1)/(x-y)】÷(2x)/(x²-2xy+y²)
计算3x[xy-2x(1/y-x/3]+3y(x²-y²)
-x³y³-x²y²+xy