log(tanθ+cotθ)sinθ=-1/4,θ∈(0,π/2),则log(tanθ)sinθ=?
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/10/04 17:22:28
log(tanθ+cotθ)sinθ=-1/4,θ∈(0,π/2),则log(tanθ)sinθ=?
需要过程.谢谢.
需要过程.谢谢.
因为(tanθ+cotθ)=1/(sinθ*cosθ),
所以,由log(tanθ+cotθ)sinθ=-1/4,得:
log(sinθ) (tanθ+cotθ)=-4,
log(sinθ) [1/(sinθ*cosθ)]=-4,
log(sinθ) (sinθ*cosθ)=4,
1+log(sinθ) (cosθ)=4,
log(sinθ) (cosθ)=3,
log(sinθ) (tanθ)=1-log(sinθ) (cosθ)=-2,
log(tanθ)sinθ=-1/2.
所以,由log(tanθ+cotθ)sinθ=-1/4,得:
log(sinθ) (tanθ+cotθ)=-4,
log(sinθ) [1/(sinθ*cosθ)]=-4,
log(sinθ) (sinθ*cosθ)=4,
1+log(sinθ) (cosθ)=4,
log(sinθ) (cosθ)=3,
log(sinθ) (tanθ)=1-log(sinθ) (cosθ)=-2,
log(tanθ)sinθ=-1/2.
sinθ-cosθ=1/2,则tanθ+cotθ=
证明1-2cos^2θ/tanθ-cotθ=sinθcosθ
已知sinθ+cosθ=√2,则tanθ+cotθ=?
sinΘ-cosΘ=1/2,求tanΘ+cotΘ
[(sinθ+tanθ)/(cscθ+cotθ)]^2=(sin^2θ+tan^2θ)/(csc^2θ+cot^2θ)
求证:sin^2θtanθ+cos^2θcotθ+2sinθcosθ=tanθ+cotθ
若sinθ+cosθ=1/3,求tanθ+cotθ.
已知tanθ+cotθ=2,求sin^3θ-cos^3θ的值
求证[tanθ·(1-sinθ)]/1+cosθ=[cotθ·(1-cosθ)]/1+sinθ
有道数学题帮下忙cot(sinθ)*tan(cosθ)
化简sin(θ-5π)•cot(π2-θ)•cos(8π-θ)tan(3π-θ)•tan(θ-32π)•sin(-θ-4
化简:cos^2θcotθ+sin^2θtanθ+2cosθsinθ