=2[1/log3(36)+1/log2(36)] =2[log36(3)+log36(2)]

已知log2(3)=a,log3(7)=b,试用a,b表示log36(45) log5(1/3) x log36 x log6a=2,求a 1.(log3 2+log9 2)(log4 3+log8 3) 2.已知log18 9=a.18^b=5.求log36 化简 (log36(4))/(log18(6))+log^2 6(3) 计算（log36(4))/(log18(6))+log^2 6(3) 对数函数问题log18 9 = a log18 5 =b 则log36 45= 用a b表示?y=log2 (x^2-a log2(3)+log3(5)+log3(2)=? log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^ log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=? log36 (45)=log18(45)/log18(36) =(log18 5+log18 9)/(log18 18 log18 9=m,18^(-n)=1/5,则log36 45=? 计算：log36（4）/log18（6）+（log6 （3））*2