一元四次方程x^4-3X^3+4=0

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/19 00:07:24

一元四次方程
x^4-3X^3+4=0

答案是 2.8220 1.3409 -0.5815 + 0.8479i -0.5815 - 0.8479i 用MATLAB求解 >> solve('x^4-3*x^3+4=0') ans = 3/4+1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+1/12*((162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)-576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) 3/4+1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-1/12*((162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)-576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) 3/4-1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+1/12*i*((-162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)+576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) 3/4-1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-1/12*i*((-162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)+576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) >> 3/4+1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+1/12*((162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)-576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) ans = 2.8220 >> 3/4+1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-1/12*((162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)-576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) ans = 1.3409 >> 3/4-1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+1/12*i*((-162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)+576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) ans = -0.5815 + 0.8479i >> 3/4-1/12*3^(1/2)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)-1/12*i*((-162*(486+6*3489^(1/2))^(1/3)*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+12*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)*(486+6*3489^(1/2))^(2/3)+576*((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2)+486*3^(1/2)*(486+6*3489^(1/2))^(1/3))/(486+6*3489^(1/2))^(1/3)/((27*(486+6*3489^(1/2))^(1/3)+4*(486+6*3489^(1/2))^(2/3)+192)/(486+6*3489^(1/2))^(1/3))^(1/2))^(1/2) ans = -0.5815 - 0.8479i

如何解一元四次方程x^4+2x^3+9-18x=0 解一元四次方程X^4+4X^3+2X^2-5X=2 一元四次方程求解~x^4+4x^3+8x^2+8x+4=0 一元四次方程求解4X^4-8X^3-(121/4)X^2+32X+64=0 一元四次方程求解..x^4-20x^3+232x^2+1320x+4353.5=0 (X+1)(X+2)(X+3)(X+4)=120 这个一元四次方程怎么解啊～! 一元四次方程X^4-7X^2+4X+4=0的解是多少? 怎样解一元四次方程例如：x^4-14x^2+x+38=0 已知关于x的一元四次方程x^4+3x^3+(k+3)x^2+(k+2)x+k=0有实数根,（1）求k的取值范围（2）若方两道一元二次题 1.若方程x²-3x-1=0的两根也是方程 4倍的x四次方+ax²+bx=0的根.求请高人来解四次方程x^4+4x^3+6x^2-8x-8=0 x四次方-3x三次方-8x平方+6x+4=0 解方程.