提取公因式计算题 急1.(b-a)2次+a(a-b)+b(b-a) 2.(3a-4b)(7a-8b)+(11a-12b)
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提取公因式计算题 急
1.(b-a)2次+a(a-b)+b(b-a) 2.(3a-4b)(7a-8b)+(11a-12b)(8b-7a)4.x(b+c-d)-y(d-b-c)-c-b+d 5.x平方+x+4分之一6.8a-4a平方-4
1.(b-a)2次+a(a-b)+b(b-a) 2.(3a-4b)(7a-8b)+(11a-12b)(8b-7a)4.x(b+c-d)-y(d-b-c)-c-b+d 5.x平方+x+4分之一6.8a-4a平方-4
1. (b-a)²+a(a-b)+b(b-a)
= (b-a)²-a(b-a)+b(b-a)
= (b-a-a+b)×(b-a)
= (2b-2a)×(b-a)
= 2(b-a)×(b-a)
= 2(b-a)²
2. (3a-4b)×(7a-8b)+(11a-12b)×(8b-7a)
= (3a-4b)×(7a-8b)-(11a-12b)×(7a-8b)
= (7a-8b)×(3a-4b-11a+12b)
= (7a-8b)×(-8a+8b)
= -8(a-b)(7a-8b)
3. x(b+c-d)- y(d-b-c)- c -b+d
= x(b+c-d)+y(b+c-d)+(b+c-d)
= (b+c-d)×(x+y+1)
4. x²+x+1/4
= (x+1/2)×(x+1/2)
= (x+1/2)²
5. 8a-4a²-4
= -(4a²-8a+4)
= -【4(a²-2a+1)】
= - 4(a-1)²
再问: 能再帮我看看这几道题吗? (a²+9)²-36a² a²-2ab+b²-c²
再答: (a²+9)²-36a² = (a²-6a+9)×(a²+6a+9) = (a-3)² ×(a+3)² a²-2ab+b²-c² = (a-b)²-c² = (a-b+c)×(a-b-c)
= (b-a)²-a(b-a)+b(b-a)
= (b-a-a+b)×(b-a)
= (2b-2a)×(b-a)
= 2(b-a)×(b-a)
= 2(b-a)²
2. (3a-4b)×(7a-8b)+(11a-12b)×(8b-7a)
= (3a-4b)×(7a-8b)-(11a-12b)×(7a-8b)
= (7a-8b)×(3a-4b-11a+12b)
= (7a-8b)×(-8a+8b)
= -8(a-b)(7a-8b)
3. x(b+c-d)- y(d-b-c)- c -b+d
= x(b+c-d)+y(b+c-d)+(b+c-d)
= (b+c-d)×(x+y+1)
4. x²+x+1/4
= (x+1/2)×(x+1/2)
= (x+1/2)²
5. 8a-4a²-4
= -(4a²-8a+4)
= -【4(a²-2a+1)】
= - 4(a-1)²
再问: 能再帮我看看这几道题吗? (a²+9)²-36a² a²-2ab+b²-c²
再答: (a²+9)²-36a² = (a²-6a+9)×(a²+6a+9) = (a-3)² ×(a+3)² a²-2ab+b²-c² = (a-b)²-c² = (a-b+c)×(a-b-c)
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