已知67^x=27,603^y=81,求3/x-4/y的值

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已知67^x=27,603^y=81,求3/x-4/y的值
我不是要用计算器算出来的答案,能讲讲方法吗?

67^x=27,603^y=81
x=log67(27),y=log603(27)
3/x-4/y
=3*log27(67)-4*log81(603)
=3*log3^3(67)-4*log3^4(603)
=log3(67)-log3(603)
=log3(67/603)
=log3(1/9)
=-2

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