(y-7)²=12 25(2x-1)²-16=0 2x²+1=3x OK?
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
(x+y)-(x+y)平方 因式分解 解方程 2x²=3x (3x-1)² - 4=0 5x-15x
y=(x²+2x+3)/x+1,x∈[0,1]的值域
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
(X-Y)²+(3X-2Y)(2X+Y)-X(6X-Y),其中X=½,Y=1(先化简再求值)
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
解方程组 y²-3x²+x+1=0 2x-y=1
解方程y²-3x²+x+1=0,2x-y=1
已知x²+y²+5=2x+4y,求代数式(2x²-(x+y)(x-y))x((x+y-1)
已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y