诺log2[log1/2(log2x)]=log3[log1/3(log3y)]=比log5[log1/5(log5z)
log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小
若log2[log12(log2x)]=log3[log13(log3y)]=log5[log15(log5z)]=0,
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log1/3(1/5),log1/5(1/3),log5(1/3),log3(1/5)比较大小
为什么log1/2x=–log2x
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
log2(log0.5(log2a))=0 log3(log1/3 (log3 b))=0 a,b的大小关系为?R
比较log2^(1/3),log1/3^2,log5^2的大小
若a=log2 3.b=log3 2,c=log1/3 2.d=log2 1/3
已知x满足2(log1/2)2+7log1/2x+3小于等于0,求y=(log2x/2)(log2x/4)的最大值与最小
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
求函数y=log1\2(1-2x-x^2)的值域 求满足不等式log2(3x-5)<log2x+1的x取值范围