求值 cos25/3π+tan(-15/4π)
三角函数的计算题目cos25/3*π=tan(-15/4*π)
求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-
计算:sin25π/6+cos25π/4+tan(-25π/4)+sin(-26π/3)
sin25π/4+cos25π/3+tan(-25π/4)=
1sin3分之4π乘以6分之cos25π乘以tan-4分之3π=
sin25/6pai+cos25/3pai+tan(-25/4pai)
反函数求值tan[arcsin(-1/4)+π/3]
求值tan(-6/23π)求值sin75度
cos25πtdt (0~π/4)的微积分怎么求?
求值tan(π/6-θ)+tan(π/6+θ)+√3tan(π/6-θ)tan(π/6+θ)
已知α=π/9,求值tanα+tan2α+根号3tanα×tan2α=( )
求值tan(kπ+π/6)cos(kπ-4π/3),k属于z