x+2/x²—2x -x-1/x²-4x化简

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/13 00:39:01

(x+2)/(x²-2x)-(x-1)/(x²-4x)
=(x+2)/[x(x-2)]-(x-1)/[x(x-4)]
=[(x+2)(x-1)-(x-1)(x-2)]/[x(x-2)(x-4)]
=[(x²+x-2)-(x²-3x+2)]/[x(x-2)(x-4)]
=(x²+x-2-x²+3x-2)/[x(x-2)(x-4)]
=(4x-4)/[x(x-2)(x-4)]
=[2(x-1)]/[x(x-2)(x-4)]
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化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以（2-x） (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 化简（x+1/x)²+2（x+1/x)+2 (4x³)²×[x³-x(2x-1)] 计算:2x/(x-2)(x+1)÷(1－x/x+1)-x²+2x/x²-4? [（x+2）/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x 化简,x²+4x /(2x-4)(x+4)-x+2/x² -4 (x+1)/(x²+3x+2)+(x²-2x)/(x²-4) x²-2x分之x+2-x²-4x+4分之x-1 x+2/x²-2x-x-1/x²-4x+4计算解方程(x²-x+4)x-(x-1)(x²+2)=x+7 (x+2)/x(x-2)-(x-1)/x²-4x+4=几,