(y²-x²)/[2(y²-xy)]化简成(y+x)/(2y)对?
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
计算:x²+2xy+y²/xy-y².x²-2xy+y²/xy+y
急![(3x+y)²-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy)
(-x-2y)(x²-2xy+4y²)
x²-xy-2y²-x-y 因式分解
x³y-2x²y²+xy³
化简:[(x+y)²-(x-y)²]÷2xy
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
化简求值:x-y/x²-2xy+y²-xy+y²/x²-y²,其中(x
化简(x²y-4y²)/(x²+4xy+4y²)*[(4xy)/(x-2y)+x
【(1)/(x-y)+(1)/(x-y)】÷(2x)/(x²-2xy+y²)
计算3x[xy-2x(1/y-x/3]+3y(x²-y²)