三角函数方程 cos^4 X - 2 sin ^2 X cos ^2 X - 3 sin ^4 = 0 如何解出 X ,

证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4 f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+/4π) 三角函数 三角函数已知P(-4,3) 求(cos((π/2)+x)sin(-π-x))/(cos((11π/2)-x)sin((9 三角函数证明及化简题1.证明sin^6x＋cos^6x＝（sin^2x＋cos^2x)（cos^4x－cos^2xsin 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 化简下面的三角函数f(x)=sin^2x+2√3sin(x+∏/4)cos(x-∏/4)-cos^2-√3 关于三角函数,sin(x/2)cos(x/2 兀/3) cos(x/2)sin(x/2 兀/3)=sin(x x 兀/3 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2 求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x). 已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x