(log(3)2+log(9)2)*(log(4)3+log(8)3) 带括号的是底数
这道对数题怎么解[log(4)3+log(8)3]*[log(3)2+log(9)2]小括号里是底数.
(1/8)^-2/3*2log的底数1/2(根号2)+4^(log的底数2^3)*log的底数8(1/9)*log的底数
如何计算啊.(log底数4真数3+log底数8真数3)乘(log底数3真数2+log底数9真数2)=?
log底数2 真数3×log底数3 真数4×log底数4 真数5×log底数5 真数2
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
log底数7[log底数3(log底数2X)]=0,那么x^1/2的值是
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
log(2)9×log(3)4
log(2)9log(3)4等于
(LOG(3,4)+LOG(3,8))(LOG(2,3)+LOG(2,9))等于几 看的懂吧