已知tana=-2求下列各值
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已知tana=-2求下列各值
(1)sina (2)sina-cosa/sina+cosa (3)sinacosa
(4)sin²a-sinacosa+4cos²a (5)sin²a+sinacosa+1
(1)sina (2)sina-cosa/sina+cosa (3)sinacosa
(4)sin²a-sinacosa+4cos²a (5)sin²a+sinacosa+1
∵ tan a = - 2 < 0
∴ a 是第二、第四象限角
∴ sin a = ± 2√5 / 5
(sin a - cos a)/ (sin a + cos a)
=(sin a - cos a)÷ cos a / (sin a + cos a)÷ cos a
=(tan a - 1)/(tan a + 1)
= (- 2 - 1)/(- 2 + 1)
= - 3 / (- 1)
= 3
sin a cos a
= sin a cos a / 1
= sin a cos a / (sin ² a + cos ² a)
= (sin a cos a ÷ cos ² a )/(sin ² a + cos ² a)÷ cos ² a
= tan a / (tan ² a + 1)
= (- 2)/((- 2)² + 1)
= - 2 / (4 + 1)
= - 2 / 5
sin ² a - sin a cos a + 4 cos ² a
=(sin ² a - sin a cos a + 4 cos ² a)/ (sin ² a + cos ² a)
= (sin ² a - sin a cos a + 4 cos ² a)÷ cos ² a / (sin ² a + cos ² a)÷ cos ² a
= (tan ² a - tan a + 4 )/ (tan ² a + 1)
= ((- 2)² -(- 2)+ 4 )/ ((- 2)² + 1)
= (4 + 2 + 4)/ (4 + 1)
= 10 / 5
= 2
sin ² a + sin a cos a + 1
= sin ² a + sin a cos a + sin ² a + cos ² a
= 2 sin ² a + sin a cos a + cos ² a
= (2 sin ² a + sin a cos a + cos ² a)/(sin ² a + cos ² a)
= (2 sin ² a + sin a cos a + cos ² a)÷ cos ² a /(sin ² a + cos ² a)÷ cos ² a
= (2 tan ² a + tan a + 1)/ (tan ² a + 1)
= (2 × (- 2)² +(- 2)+ 1)/((- 2)² + 1)
= (2 × 4 - 2 + 1)/(4 + 1)
= (8 - 1)/ 5
= 7 / 5
∴ a 是第二、第四象限角
∴ sin a = ± 2√5 / 5
(sin a - cos a)/ (sin a + cos a)
=(sin a - cos a)÷ cos a / (sin a + cos a)÷ cos a
=(tan a - 1)/(tan a + 1)
= (- 2 - 1)/(- 2 + 1)
= - 3 / (- 1)
= 3
sin a cos a
= sin a cos a / 1
= sin a cos a / (sin ² a + cos ² a)
= (sin a cos a ÷ cos ² a )/(sin ² a + cos ² a)÷ cos ² a
= tan a / (tan ² a + 1)
= (- 2)/((- 2)² + 1)
= - 2 / (4 + 1)
= - 2 / 5
sin ² a - sin a cos a + 4 cos ² a
=(sin ² a - sin a cos a + 4 cos ² a)/ (sin ² a + cos ² a)
= (sin ² a - sin a cos a + 4 cos ² a)÷ cos ² a / (sin ² a + cos ² a)÷ cos ² a
= (tan ² a - tan a + 4 )/ (tan ² a + 1)
= ((- 2)² -(- 2)+ 4 )/ ((- 2)² + 1)
= (4 + 2 + 4)/ (4 + 1)
= 10 / 5
= 2
sin ² a + sin a cos a + 1
= sin ² a + sin a cos a + sin ² a + cos ² a
= 2 sin ² a + sin a cos a + cos ² a
= (2 sin ² a + sin a cos a + cos ² a)/(sin ² a + cos ² a)
= (2 sin ² a + sin a cos a + cos ² a)÷ cos ² a /(sin ² a + cos ² a)÷ cos ² a
= (2 tan ² a + tan a + 1)/ (tan ² a + 1)
= (2 × (- 2)² +(- 2)+ 1)/((- 2)² + 1)
= (2 × 4 - 2 + 1)/(4 + 1)
= (8 - 1)/ 5
= 7 / 5
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