In the standard(x,y) coordinate plane,what is the equation o
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In the standard(x,y) coordinate plane,what is the equation of the line whose points are equidistant from the
points (2,4)and (-4,6)?
A.5x-y=10 B.3x+y=2 C.3x-y=-8 D.x-3x=16 E.x+3y=14
points (2,4)and (-4,6)?
A.5x-y=10 B.3x+y=2 C.3x-y=-8 D.x-3x=16 E.x+3y=14
选C
在标准的(x,y)坐标平面,从点(2,4)和点(-4,6)等距的线方程是什么?
点(2,4)和点(-4,6)中点是【(2-4)/2,(4+6)/2】=(-1,5),方程是y=-1/3x+22/3
与y=-1/3x+22/3垂直的方程,k=3,设y=3x+b
经过点(-1,5),则b=8
所以y=3x+8,即3x-y=-8
在标准的(x,y)坐标平面,从点(2,4)和点(-4,6)等距的线方程是什么?
点(2,4)和点(-4,6)中点是【(2-4)/2,(4+6)/2】=(-1,5),方程是y=-1/3x+22/3
与y=-1/3x+22/3垂直的方程,k=3,设y=3x+b
经过点(-1,5),则b=8
所以y=3x+8,即3x-y=-8
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