计算:[(3x+1)(9x^2-3x+1)+(3x-1)(9x^+3x+1)]÷[(4x+1)^
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
4x²-1/3x²-x·9x³-x/2x^4-x³计算 急
计算(1+1/x)÷(2x-1+x²/x) 2x/x²-9+1/3-x+x+2/x+3
计算:再问一题:(3x^2+9x+7)/(x+1)-(2x^2-4x+3)/(x-1)-(x^3+x+1)/(x^2-1
计算:(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算
计算:(x+1)x=7 (x-1)(x+2)=30 (3-x)(3-x)+x=9