求证tan^2asin^2a=tan^2a-sin^2a
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/10/01 04:37:31
求证tan^2asin^2a=tan^2a-sin^2a
求证tan^2 a 乘 sin^2 a=tan^2 a-sin^2 a
求证tan^2 a 乘 sin^2 a=tan^2 a-sin^2 a
tan^2 a 乘 sin^2 a
=sin^2 a/cos^2 a*sin^2 a
=sin^4 a/cos^2a
tan^2a-sin^2a
=sin^2 a/cos^2a-sin^2a
=(sin^2 a-sin^2 a*cos^2a)/cos^2a
=sin^2 a(1-cos^2 a)/cos^2a
=sin^4 a/cos^2a
故:tan^2asin^2a=tan^2a-sin^2a.
=sin^2 a/cos^2 a*sin^2 a
=sin^4 a/cos^2a
tan^2a-sin^2a
=sin^2 a/cos^2a-sin^2a
=(sin^2 a-sin^2 a*cos^2a)/cos^2a
=sin^2 a(1-cos^2 a)/cos^2a
=sin^4 a/cos^2a
故:tan^2asin^2a=tan^2a-sin^2a.
求证[1]1-2sin acos a/cos²a -sin²a =1-tan a/1+tan a.[
求证sin与tan 已知3sinB=sin(2A+B),求证tan(A+B)=2tanA
证明:(1+tan a+cot a)/(1+tan^2 a+tan a)-cot a/(1+ tan^2 a)=sin
求证:tan a/2=(1-cos)/sin a=sin a/(cos a+1)
tan^2a =2tan^2b+1 求证 cos2a +sin^2b=0
sin^2(-a)-tan(360-a)tan(-a)-sin(180-a)cos(360-a)tan(180+a)=
求证1/(sin^2)a+1/(cos^2)a-1/(tan^2)a=2+(tan^2)a
已知tan^2A=2tan^B+1求证sin^2B=2sin^2A-1
已知sin^2B=2sin^2A-1求证tan^2A=2tan^B+1
已知tan^2 a=2tan^ B +1,求证sin^2 b=sin^2 a -1
已知tan(A-B)/tanA+sin^2C/sin^2A=1,求证:tanA*tanB=tan^2C
已知tan(a-r)/tana+sin^2b/sin^2a=1 ,求证tan^2b=tana*tanr..